This problem appears at the Qualifying Examinations for Applicants for Japanese Government (MEXT) Scholarships 2020 . There are two mathematics exams: one for biology-related natural sciences (Mathematics A), and another for physics- and engineering-related natural sciences (Mathematics B). This problem is from the 2020 Mathematics (B) questionnaire . The official answer key is here . Problem 1(4) The division of a polynomial function f(x) by (x-1)^2 gives the remainder of x+1, and that by x^2 gives the remainder 2x+3. Thus, the remainder of the division of f(x) by x^2(x-1) is \fbox{ A }x^2 + \fbox{ B }x + \fbox{ C } . Solution We need to find the remainder when f(x) is divided by x^2(x-1). Because x^2(x-1) is of order n=3, the remainder will be of at most the order n=2, which means that it is of the form Ax^2 + Bx + C. The problem is now to find the coefficients A,B and C such that ...
Comments
Post a Comment